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Question
Given A = `[(-3, 6),(0, -9)]` and At is its transpose matrix. Find `A^t - 1/3 A`
Solution
`A^t - 1/3 A`
= `[(-3, 0),(6, -9)] - 1/3 [(-3, 6),(0, -9)]`
= `[(-3, 0),(6, -9)] - [(-1, 2),(0, -3)]`
= `[(-3 - (-1), 0 - 2),(6 - 0, -9 - (-3))]`
= `[(-3 + 1, -2),(6, -9 + 3)]`
= `[(-2, -2),(6, -6)]`
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