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Question
Given `A = [(2, 1),(3, 0)], B = [(1, 1),(5, 2)]` and `C = [(-3, -1),(0, 0)]`; find 2A – 3B + C
Solution
2A – 3B + C
= `2[(2, 1),(3, 0)] -3[(1, 1),(5, 2)] + [(-3, -1),(0, 0)]`
= `[(4, 2),(6, 0)] - [(3, 3),(15, 6)] + [(-3, -1),(0, 0)]`
= `[(4 - 3 - 3, 2 - 3 - 1),(6 - 15 + 0, 0 - 6 + 0)]`
= `[(4 - 6, 2 - 4),(6 - 15, -6)]`
= `[(-2, -2),(-9, -6)]` or `-[(2, 2),(9, 6)]`
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