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Question
A 12 litre solution is `33(1)/(2)` acid. How much water must be added to get the solution having 20% acid?
Solution
Let the amount of water be x litres.
Volume of acid in the solution
= `33(1)/(3)%` of 12 litres
= `(100)/(3)`% x 12
= `(100)/(300) xx12`
= 4litres
Concentration of acid in (12 + x)litres of solution = 20%
⇒ `(4)/(12 + x) = (20)/(100)`
⇒ `(4)/(12 + x) = (1)/(5)`
⇒ 12 + x = 20
⇒ x = 8litres
Hence, 8litres of water should be added.
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