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Question
A 2-digit number is such that the product of its digits is 24. If 18 is subtracted from the number, the digits interchange their places. Find the number.
Solution
Let the ten's digit be x and the one's digit be y.
The number will be 10x + y
Given, a product of digits is 24
∴ xy = 24
or, y = `24/x` ...(i)
Given that when 18 is subtracted from the number, the digits interchange their places.
∴ 10x + y – 18 = 10y + x
or, 9x – 9y = 18 ...(ii)
Substituting y from equation (i) in equation (ii), we get
`9x - 9 (24/x)` = 18
or, `x - 24/x` = 2
or, x2 – 24 – 2x = 0
or, x2 – 2x – 24 = 0
or, x2 – 6x + 4x – 24 = 0
or, x(x – 6) + 4(x – 6) = 0
or, (x – 6)(x + 4) = 0
or, x – 6 = 0 and x + 4 = 0
or, x = 6 and x = −4
Since, the digit cannot be negative, so, x = 6
Substituting x = 6 in equation (i), we get
y = `24/6` = 4
∴ The number = 10(6) + 4 = 60 + 4 = 64
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