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Question
A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue ball is ______.
Options
`3/28`
`2/21`
`1/28`
`167/168`
Solution
A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue ball is `3/28`.
Explanation:
Probability of drawing 2 green and 1 blue balls
= P(G) . P(G) . P(B) + P(G) . P(B) . P(G) + P(B) . P(G) . P(G)
= `3/8*2/7*2/6 + 3/8*2/7*2/6 + 2/8*3/7*2/6`
= `12/336 + 12/336 + 12/336`
= `36/336`
= `3/28`
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