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A candidate is required to answer 7 questions out of 12 questions, which are divided into two groups, each containing 6 questions. He is not permitted to attempt more than 5 questions from either - Mathematics

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Question

A candidate is required to answer 7 questions out of 12 questions, which are divided into two groups, each containing 6 questions. He is not permitted to attempt more than 5 questions from either group. Find the number of different ways of doing question

Sum

Solution

Total number of questions = 12

Number of questions in each group = 6

7 questions are to be attempted but not more than 5 questions from either group

∴ Total number of ways = 6C5 × 6C2 × 6C4 × 6C3 + 6C3 × 6C4 + 6C2 × 6C5

= 2[6C5 × 6C2 + 6C4 × 6C3]

= `2[6 xx (6.5)/(2.1)  + (6*5*4*3)/(4*3*2*1) xx (6*5*4)/(3*2*1)]`

= 2[6 × 15 + 15 × 20]

= 2[90 + 300]

= 2 × 380

= 780

Hence, the total number of ways = 780

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Chapter 7: Permutations and Combinations - Exercise [Page 122]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Exercise | Q 3 | Page 122

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