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Question
A capacitor of capacitance 0.5 μF is connected to a source of alternating e.m.f. of frequency 100 Hz. What is the capacitive reactance? (Π = 3.142)
Solution
C = `0.5 xx 10^(-6)`
f = 100 Hz
`X_c =1/(omegaC)`
`= 1/(2pifxxC)`
`= 1/(2xx3.14 xx 100xx0.5xx10^(-6))`
`= 1/(2 xx 3.14 xx 0.5 xx 10^(-4))`
`= 10^(-4)/3.142`
= 3182.68 Ω
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