Advertisements
Advertisements
Question
A cheetah starts from, rest, and accelerates at 2 m/s2 for 10 seconds. Calculate :
(a) the final velocity
(b) the distance travelled.
Solution
We have to find the distance travelled by the cheetah. We have the following information given,
So, initial velocity, (u) = 0 m/s
Acceleration, (a) = 2 m/s2
Time taken, (t) = 10 s
(a) So, we can find the final velocity using the relation, v = u + at
Final velocity,
v = 0 + (2) (10)
= 20 m/s
(b) We can calculate the distance travelled by cheetah using the 2nd equation of motion,
`s = ut + 1/2 at^2`
Put the values in above equation to find the distance travelled
`(s) = 0(10) + 1/2(2)(10)^2`
= 100 m
APPEARS IN
RELATED QUESTIONS
A bus decreases its speed from 80 km h−1 to 60 km h−1 in 5 s. Find the acceleration of the bus.
A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h−1 in 10 minutes. Find its acceleration.
Give one example of a situation in which a body has a certain average speed but its average velocity is zero.
Explain the meaning of the following equation of motion :v = u + at, where symbols have their usual meanings.
State how the velocity-time graph can be used to find
The acceleration of a body
Derive the following equations for uniformly accelerated motion:
(i) v = u + at
(ii) `"S = ut" + 1/2 "at"^2`
(iii) v2 = u2 + 2aS
where the symbols have their usual meanings.
When is the negative acceleration?
Multiple choice Question. Select the correct option.
The speed of a car reduces from 15 m/s to 5 m/s over a displacement of 10 m. The uniform acceleration of the car is :
Multiple choice Question. Select the correct option.
At the maximum height, a body thrown vertically upwards has :
A packet is dropped from a stationary helicopter, hovering at a height ‘h’ from ground level, reaches the ground in 12s. Calculate
- the value of h
- final velocity of packet on reaching the ground. (Take g = 9.8 ms−2)