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Question
A train travelling at 20 m s-1 accelerates at 0.5 m s-2 for 30 s. How far will it travel in this time ?
Solution
We have to find the distance travelled by the train. We have the following information given,
So, initial velocity, (u) = 20 m/s
Acceleration, (a) = 0.5 m/s2
Time taken, (t) = 30 s
We can calculate the distance travelled by using the 2nd equation of motion,
`s = ut + 1/2at^2`
Put the values in above equation to find the distance travelled by the train,
`(s) = 20(30) + 1/2(0.5)(30)^2`
= (600 + 225) m
= 825 m
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