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Question
A body is thrown vertically upward with velocity u, the greatest height h to which it will rise is,
Options
`"u"/"g"`
`"u"^2/(2"g")`
`"u"^2/"g"`
`"u"/(2"g")`
Solution
`"u"^2/(2"g")`
At highest point, v = 0
Using v2– u2 = 2as, we get
0 − u2 = 2(−g)h ( ∵ a = −g and s = h)
or h = `"u"^2/(2"g")`
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