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Question
A chord of length 8cm is drawn inside a circle of radius 6cm. Find the perpendicular distance of the chord from the centre of the circle.
Solution
AC = CB = 4cm
(Perpendicular from centre to a chord bisects the chord)
In right Δ ABO,
By Pythagoras theorem, OA2 = OC2 + AC2
OC2 - 62 + 42
OC = 36 - 16 = 20
OC2 = `2 sqrt 5` cm
Perpendicular distance of chord from centre is `2 sqrt 5` cm
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