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Question
A chord of length 6 cm is drawn in a circle of radius 5 cm.
Calculate its distance from the center of the circle.
Solution
Let AB be the chord and O be the center of the circle.
Let OC be the perpendicular drawn from O to AB.
We know, that the perpendicular to a chord, from the center of a circle, bisects the chord.
∴ AC = CB = 3 cm
In ΔOCA,
OA2 = OC2 + AC2 ...( By Pythagoras theorem )
⇒ OC2 = (5)2 - (3)2
⇒ OC = 16
⇒ OC = 4 cm
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