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Question
The radius of a circle is 13 cm and the length of one of its chords is 24 cm.
Find the distance of the chord from the center.
Solution
To find: OM
Given that AB = 24 cm
Since OM ⊥ AB
⇒ OM bisects AB
So, AM = 12 cm
In right ⇒ OMA,
OA2 = OM2 + AM2
OM2 = OA2 - AM2
OM2 = 132 - 122
OM2 = 25
OM2 = 5 cm
Hence, the distance of the chord from the centre is 5 cm.
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