Advertisements
Advertisements
Question
A cylindrical vessel having diameter equal to its height is full of water which is poured into two identical cylindrical vessels with diameter 42cm and height 21cm which are filled completely. Find the diameter of cylindrical vessel?
Solution
Given that diameter is equal to height of a cylinder
so h = 2π
Volume of cylinder=πr2h
So volume = πr2(2r)
2πr3
Volume of each vessel =πr2h
Diameter = 42cm
Height = 21cm
Diameter(d) = 2r
2r = 42
r = 21
∴ Radius = 21cm
Volume of vessel = π(21)2x21 ...........(2)
Since volumes are equal
Equating (1) and (2)
⇒ 2πr3= π(21)2 x 21 x 2 (∵ 2 identical vessels)
⇒ `r^2=(pi(21)^2xx21xx2)/(2xxpi)`
⇒ r3 = (21)3
⇒ r = 21 ⇒ d = 42cm
∴ Radius of cylindrical vessel = 21cm
Diameter of cylindrical vessel= 42 cm.
APPEARS IN
RELATED QUESTIONS
The volume of a hemisphere is 2425`1/2cm^3`cm. Find its curved surface area?
A cylinder with base radius 8 cm and height 2 cm is melted to form a cone of height 6 cm. Calculate the radius of the base of the cone.
Find the ratio of the volumes of a cylinder, a cone and a sphere, if each has the same diameter and same height?
Rainfall in an area is 5 cm. The volume of the water that falls on 2 hectares of land is
A metallic cylinder of radius 8 cm and height 2 cm is melted and converted into a right circular cone of height 6 cm. The radius of the base of this cone is
Two right circular cylinders of equal volumes have their heights in the ratio 1 : 2. What is the ratio of their radii?
Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/hour. How much area will it irrigate in 30 minutes; if 8 cm standing water is needed?
The volume of a right circular cylinder is 345 cm³. Then, the volume of a right circular cone whose radius of the base and height is the same as of circular cylinder will be ______.
A solid piece of iron in the form of a cuboid of dimensions 49 cm × 33 cm × 24 cm, is moulded to form a solid sphere. The radius of the sphere is ______.
How many cubic centimetres of iron is required to construct an open box whose external dimensions are 36 cm, 25 cm and 16.5 cm provided the thickness of the iron is 1.5 cm. If one cubic cm of iron weighs 7.5 g, find the weight of the box.