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Question
Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/hour. How much area will it irrigate in 30 minutes; if 8 cm standing water is needed?
Solution
The canal is 6 m wide and 1.5 m deep. The water is flowing in the canal at 10 km/hr. Hence, in 30 minutes, the length of the flowing standing water is
= `10 xx(30)/(60)"km"`
= 5 km
= 5000 m
Therefore, the volume of the flowing water in 30min is
`"V"_1 = 5000 xx 1.5 xx 6 "m"^3`
Thus, the irrigated area in 30 min of 8 cm = 0.08 m standing water is
= `(5000 xx 1.5 xx6)/(0.08)`
= 562500m2
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