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Question
A game of chance consists of spinning an arrow which is equally likely to come to rest
pointing to one of the number, 1, 2, 3, ..., 12 as shown in Fig. below. What is the
probability that it will point to a number which is multiple of 3?
Solution
Total no. of possible outcomes = 12 {1, 2, 3,…., 12}
Let E ⟶ event of pointing at a no. multiple of 3
No. favourable outcomes = 4 {3, 6, 9, 12}
P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
P(E) =4/12 =1/3
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