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A Heap of Rice in the Form of a Cone of Diameter 9 M and Height 3.5 M. Find the Volume of Rice. How Much Canvas Cloth is Required to Cover the Heap ? - Mathematics

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Question

A heap of rice in the form of a cone of diameter 9 m  and height 3.5 m. Find the volume of rice. How much canvas cloth is required to cover the heap  ?

Answer in Brief

Solution

The heap of rice is in the form of a cone.
Diameter, d = 9 m
radius, r =  \[\frac{9}{2}m\]

height, h = 3.5 m

\[\text { Volume }, V = \frac{1}{3} \pi r^2 h\]

\[ = \frac{1}{3}\pi \left( \frac{9}{2} \right)^2 \times 3 . 5\]

\[ = 74 . 25 m^3\]

Thus, volume of rice = 74.25 m3
The canvas cloth required to cover the heap will be the curved surface area of the cone

\[l = \sqrt{h^2 + r^2}\]

\[l = \sqrt{3 . 5^2 + \left( \frac{9}{2} \right)^2}\]

\[l = \sqrt{12 . 25 + 20 . 25}\]

\[l = 5 . 7 m\]

\[CSA = \pi rl\]

\[ = \pi \times \left( \frac{9}{2} \right) \times 5 . 7\]

\[ = 80 . 62 m^2\]

Hence, the canvas cloth required to cover the heap will be 80.62 m2

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Chapter 14: Surface Areas and Volumes - Exercise 14.1 [Page 32]

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RD Sharma Mathematics [English] Class 10
Chapter 14 Surface Areas and Volumes
Exercise 14.1 | Q 68 | Page 32

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