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Question
The circular ends of a bucket are of radii 35 cm and 14 cm and the height of the bucket is 40 cm. Its volume is
Options
60060 cm3
80080 cm3
70040 cm3
80160 cm3
Solution
80080 cm3
Let R and r be the radii of the top and base of the bucket, respectively, and let h be its height.
Then,
R = 35 cm, r = 14 cm , h = 40 cm
R = 35 cm, r = 14 cm, h = 40 cm
Volume of the bucket = Volume of the frustum of the cone
`=1/3pi"h"["R"^2 +"r"^2+"Rr" ] "cm"^3`
`= 1/3 xx22/7xx40xx[(35)^2 + (14)^2 + (35xx14)] "cm"^3`
`=((880)/(21)xx1911) "cm"^3`
= 80080 cm3
Hence, the volume of the bucket is 80080 cm3.
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