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Question
A hypothetical thermodynamic cycle is shown in the figure. Calculate the work done in 25 cycles.
Solution
Work done in 1 cycle = Area enclosed
by the PV curve.
= `π/4 × ("P"_2 - "P"_1)("V"_2 - "V"_1)`
`= π/4 × [(11 - 1)× 10^5][(6 - 2)× 10^-3]`
`= π/4 × (10^6)(4 × 10^-3)`
`= π × 10^3`
`= 3.14 × 10^3` J
Work done in 25 cycles
`= 25×3.14×10^3`
`= 7.85 × 10^4` J.
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