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A job production unit has four jobs A, B, C, D which can be manufactured on each of the four machines P, Q, R and S. The processing cost of each job for each machine is given in the following table: - Mathematics and Statistics

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A job production unit has four jobs A, B, C, D which can be manufactured on each of the four machines P, Q, R and S. The processing cost of each job for each machine is given in the following table:

Jobs Machines
(Processing Cost in ₹)
P Q R S
A 31 25 33 29
B 25 24 23 21
C 19 21 23 24
D 38 36 34 40

Find the optimal assignment to minimize the total processing cost.

Sum

Solution

Step 1: Row minimum
Subtract the smallest element in each row from every element in its row. The matrix obtained is given below:

Jobs Machines
(Processing Cost in ₹)
P Q R S
A 6 0 8 4
B 4 3 2 0
C 0 2 4 5
D 4 2 0 6

Step 2: Column minimum
Subtract the smallest element in each column of assignment matrix obtained in step 1 from every element in its column.

Jobs Machine
(Processing Cost in ₹)
P Q R S
A 6 0 8 4
B 4 3 2 0
C 0 2 4 5
D 4 2 0 6

Step 3:
Draw minimum number of vertical and horizontal lines to cover all zeros.
First cover all rows and columns which have maximum number of zeros.

Jons Machines
(Processing Cost in ₹)
P Q R S
A 6 0 8 4
B 4 3 2 0
C 0 2 4 5
D 4 2 0 6

Step 4:
From step 3, minimum number of lines covering all the zeros are 4, which is equal to order of the matrix, i.e., 4
∴ Select a row with exactly one zero, enclose that zero in () and cross out all zeros in its respective column.
Similarly, examine each row and column and mark the assignment ().
∴ The matrix obtained is as follows:

Jobs Machines
(Processing Cost in ₹)
P Q R S
A 6 0 8 4
B 4 3 2 0
C 0 2 4 5
D 4 2 0 6

Step 5:
The matrix obtained in step 4 contains exactly one assignment for each row and column.
∴ Optimal assignment schedule is as follows:

Jobs Machines Processing cost (₹)
A Q 25
B S 21
C P 19
D R 34

∴ Total minimum processing cost = 25 + 21 + 19 + 34 = ₹ 99.

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Chapter 7: Assignment Problem and Sequencing - Exercise 7.1 [Page 118]

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Balbharati Mathematics and Statistics 2 (Commerce) [English] 12 Standard HSC Maharashtra State Board
Chapter 7 Assignment Problem and Sequencing
Exercise 7.1 | Q 1 | Page 118

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A job production unit has four jobs P, Q, R, S which can be manufactured on each of the four machines I, II, III and IV. The processing cost of each job for each machine is given in the following table :

Job Machines
(Processing cost in ₹)
I II III IV
P 31 25 33 29
Q 25 24 23 21
R 19 21 23 24
S 38 36 34 40

Complete the following activity to find the optimal assignment to minimize the total processing cost.

Solution:

Step 1: Subtract the smallest element in each row from every element of it. New assignment matrix is obtained as follows :

Job Machines
(Processing cost in ₹)
I II III IV
P 6 0 8 4
Q 4 3 2 0
R 0 2 4 5
S 4 2 0 6

Step 2: Subtract the smallest element in each column from every element of it. New assignment matrix is obtained as above, because each column in it contains one zero.

Step 3: Draw minimum number of vertical and horizontal lines to cover all zeros:

Job Machines
(Processing cost in ₹)
I II III IV
P 6 0 8 4
Q 4 3 2 0
R 0 2 4 5
S 4 2 0 6

Step 4: From step 3, as the minimum number of straight lines required to cover all zeros in the assignment matrix equals the number of rows/columns. Optimal solution has reached.

Examine the rows one by one starting with the first row with exactly one zero is found. Mark the zero by enclosing it in (`square`), indicating assignment of the job. Cross all the zeros in the same column. This step is shown in the following table :

Job Machines
(Processing cost in ₹)
I II III IV
P 6 0 8 4
Q 4 3 2 0
R 0 2 4 5
S 4 2 0 6

Step 5: It is observed that all the zeros are assigned and each row and each column contains exactly one assignment. Hence, the optimal (minimum) assignment schedule is :

Job Machine Min.cost
P II `square`
Q `square` 21
R I `square`
S III 34

Hence, total (minimum) processing cost = 25 + 21 + 19 + 34 = ₹`square`


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