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A Metal Ball Cools from 64 °C to 50 °C in 10 Minutes and to 42 °C in Next 10 Minutes. the Ratio of Rates of Fall of Temperature During the Two Intervals is _______. - Physics

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Question

A metal ball cools from 64 °C to 50 °C in 10 minutes and to 42 °C in next 10 minutes. The ratio of rates of fall of temperature during the two intervals is _______.

Options

  • 47

  • 74

  • 2

  • 2.5

MCQ

Solution

74

Rate of fall of temperature in first 10 minutes = R1 = 64-5010.°C/min = 1.4°C/min

Rate of fall of temperature in next 10 minutes = R2 = 50-4210.°C/min = 0.8°C/min

R1R2=74

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2013-2014 (March)

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