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Question
A particle performing linear S.H.M. has a period of 6.28 seconds and a pathlength of 20 cm. What is the velocity when its displacement is 6 cm from mean position?
Solution
Given:
T = 6.28s
Pathlength 20cm
∴ a =10 cm = 10×10-2m
x = 6 ×10-2m
To find:
Velocity, v = ?
Solution:
`omega = (2pi)/t`
`omega = (2xx3.14)/6.28`
`omega = 1"rad/s"`
`"V" = "W" sqrt ("A"^2 - "x"^2)`
`= 1 sqrt ((10^2 - 6^2) xx 10 ^-4)`
`v = sqrt((100-36)xx10^-4)`
`v = 1 xx 8 xx 10^-2`
`v=8 xx 10^-2 "m/s"`
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