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Question
Two particles perform linear simple harmonic motion along the same path of length 2A and period T as shown in the graph below. The phase difference between them is ___________.
Options
Zero rad
`pi/4` rad
`pi/2` rad
`(3pi)/4` rad
Solution
` pi/4 rad`
Let the equation of waves be Asin( ωt + Φ )
For wave with peak at t = 0, the equation becomes,
y = Asin( ωt + 90° )
For the wave with displacement `A/sqrt2 at t` = 0
`A/sqrt2 = Asin(Φ)`
⇒ Φ = 45° = `pi/4`
Hence this is the phase difference between the waves.
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