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A Solid Cube of Side 12 Cm is Cut into 8 Identical Cubes. What Will Be the Side of the New Cube? Also, Find the Ratio Between the Surface Area of the Original Cube and the Total Surface Area - Mathematics

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Question

A solid cube of side 12 cm is cut into 8 identical cubes. What will be the side of the new cube? Also, find the ratio between the surface area of the original cube and the total surface area of all the small cubes formed.

Sum

Solution

Here, the cube of side 12 cm is divided into 8 cubes of side 9 cm.

Given that,

Their volumes are equal.

The volume of big cube of 12 cm = Volume of 8 cubes of side a cm

(Side of the big cube)3 = 8 x (Side of the small cube)3
(12)3 = 8 x a3

⇒ `a^3 = (12 xx 12 xx 12)/8`

⇒ `a^3 = 6^3` cm3

⇒ a = 6 cm

Ratio of their surface = `"Surface area of the original cube"/"Total surface area of the small cube"`

= `(6("side of big cube")^2)/(8 xx 6("side of small cube")^2)`

= `(6 xx 12 xx 12)/(8 xx 6 xx 6 xx 6) = 4/8 = 1:2`

So, the ratio is 1:2

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Chapter 21: Surface Area, Volume and Capacity - Exercise 21 (E) [Page 244]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 21 Surface Area, Volume and Capacity
Exercise 21 (E) | Q 8 | Page 244

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