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Question
A spherical glass vessel has a cylindrical neck that is 7 cm long and 4 cm in diameter. The diameter of the spherical part is 21 cm. Find the quantity of water the vessel can hold.
Solution
Diameter of spherical part = 21 cm
Radius of the spherical part = 10.5 cm
`=4/3pir^3 = 4/3xx22/7xx10.5xx10.5xx10.5=4851 "cm"^3`
Diametere of cylinder = 4 cm
Radius of cylinder = 2 cm
Height of cylinder = 7 cm
Volume of the part of vessel `= pir^2h = 22/7xx2xx2xx7 = 88 "cm"^3`
Total volume of the vessel =4851 + 88 = 4939 cm3
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Match the column:
| (1) surface area of cuboid | (A) πr2h |
| (2) surface area of closed right cylinder | (B) 2πr(h + r) |
| (3) Total surface area of right cone | (C) πrl + πr2 |
| (4) Total surface area of hemisphere | (D) 3πr3 |
| (E) 3πr2 | |
| (F) 2[lb + bh + lh] |
