Advertisements
Advertisements
Question
A toroid has a core (non-ferromagnetic) of inner radius 25 cm and outer radius 26 cm, around which 3500 turns of a wire are wound. If the current in the wire is 11 A, what is the magnetic field (a) outside the toroid, (b) inside the core of the toroid, and (c) in the empty space surrounded by the toroid?
Solution
Inner radius of the toroid, r1 = 25 cm = 0.25 m
Outer radius of the toroid, r2 = 26 cm = 0.26 m
Number of turns on the coil, N = 3500
Current in the coil, I = 11 A
(a) Magnetic field outside a toroid is zero. It is non-zero only inside the core of a toroid.
(b) Magnetic field inside the core of a toroid is given by the relation,
B = `(μ_0"NI")/"l"`
Where,
μ0 = Permeability of free space = 4π × 10−7 T mA−1
l = length of toroid
= `2π [("r"_1 + "r"_2)/2]`
= π(0.25 + 0.26)
= 0.51 π
∴ B = `(4π xx 10^-7 xx 3500 xx 11)/(0.51 π)`
≈ 3.0 × 10−2 T
(c) Magnetic field in the empty space surrounded by the toroid is zero.
APPEARS IN
RELATED QUESTIONS
What can be the causes of helical motion of a charged particle?
An iron ring of relative permeability µr has windings of insulated copper wire of n turns per meter. When the current in the windings is I, find the expression for the magnetic field in the ring.
Magnetic field lines can be entirely confined within the core of a toroid, but not within a straight solenoid. Why?
A tightly-wound, long solenoid has n turns per unit length, a radius r and carries a current i. A particle having charge q and mass m is projected from a point on the axis in a direction perpendicular to the axis. What can be the maximum speed for which the particle does not strike the solenoid?