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Question
∠ACB is inscribed in arc ACB of a circle with centre O. If ∠ACB = 65°, find m(arc ACB).
Options
65°
130°
295°
230°
Solution
230°
Explanation:
∠ACB = `1/2 "m"("arc AB")` ...[Inscribed angle theorem]
∴ `65^\circ = 1/2 "m"("arc AB")`
∴ m(arc AB) = 130°
∴ m(arc ACB) = 360° − m(arc AB)
= 360° − 130°
= 230°
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