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Question
In the figure, two chords AB and CD of the same circle are parallel to each other. P is the centre of the circle. show that ∠CPA = ∠DPB.
Solution
CD || AB (Given)
⇒ CP = OP (Radius)
⇒ AP = PB (Radius)
⇒ ∴ ∠PCD = ∠PAB
⇒ PDC = ∠PBA
Hence, = ∠DPB
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