Advertisements
Advertisements
Question
Account for the following :
Ti4+ is colourless whereas V4+ is coloured in an aqueous solutions.
Solution
`"_22 Ti = [Ar]3d 4s^2`
22Ti4+ = [Ar]3d3 4S0 → No electrons for excitation so 4 Ti4+ is colourless.
23V = [Ar]3d3 4s2
V4+ = 3d1 4s0 → 1 electron is there for excitation and it impart blue colour in aquous
APPEARS IN
RELATED QUESTIONS
The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co
Answer the following: Which element has the highest m.p?
How would you account for the following:
The d1 configuration is very unstable in ions.
How would you account for the following?
Zr (Z = 40) and Hf (Z = 72) have almost identical radii.
Why do transition elements show variable oxidation states ? In 3d series (Sc to Zn), which elements shows the maximum number of oxidation state and why ?
Why does copper not replace hydrogen from acids?
Although \[\ce{Cr^3+}\] and \[\ce{Co^2+}\] ions have same number of unpaired electrons but the magnetic moment of \[\ce{Cr^3+}\] is 3.87 B.M. and that of \[\ce{Co^2+}\] is 4.87 B.M. Why?
Write the number of unpaired electrons in Cr3+.
(Atomic number of Cr = 24)
Account for the following:
Copper has an exceptionally positive `"E"_("M"^(2+)//"M")^0` value.
A pair of coloured ions is ______.
Why are interstitial compounds well known for transition metals?
