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An Electric Motor Pump is 60% Efficient and is Rated 2.5 H.P. Calculate the Maximum Load It Can Lift Through a Height of 10m in 8 Sec. (1 H.P. = 750 W). - Physics

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Question

An electric motor pump is 60% efficient and is rated 2.5 H.P. Calculate the maximum load it can lift through a height of 10m in 8 sec. (1 H.P. = 750 W).

Numerical

Solution

Useful power supplied by the motor =`(2.5xx750 xx60)/100` watt

= 1125 watt

If maximum load lifted is W kg, then :

Work done in lifting up the load = W × 10 × 10 J

And Work done by the pump = 1125 × 8

Or Load lifted; W =`(1125xx8)/(10xx10)` = 90 kg.

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Chapter 1: Force, Work, Power and Energy - Long Numerical

APPEARS IN

ICSE Physics [English] Class 10
Chapter 1 Force, Work, Power and Energy
Long Numerical | Q 12

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