Advertisements
Advertisements
Question
An infinitely long positively charged straight wire has a linear charge density λ. An electron is revolving in a circle with a constant speed v such that the wire passes through the centre, and is perpendicular to the plane, of the circle. Find the kinetic energy of the electron in terms of the magnitudes of its charge and linear charge density λ on the wire.
Solution
Infinitely long charged wire produces a radial electric field.
E = `lambda/(2piε_0r)` .............(i)
The revolving electron experiences an electrostatic force and provides the necessary centripetal force.
∴ eE = `(mv^2)/r` ...............(ii)
⇒ `(e.lambda)/(2piε_0r) = (mv^2)/r ⇒ mv^2 = (elambda)/(2piε_0)`
The kinetic energy of the electron,
K = `1/2mv^2 = (elambda)/(4piε_0)`
APPEARS IN
RELATED QUESTIONS
A 36 cm long sonometer wire vibrates with frequency of 280 Hz in fundamental mode, when it is under tension of 24.5 N. Calculate linear density of the material of wire.
Explain why, for a charge configuration, the equipotential surface through a point is normal to the electric field at that point
A point charge causes an electric flux of −1.0 × 103 Nm2/C to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge.
- If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?
- What is the value of the point charge?
A point charge q is at a distance of d/2 directly above the centre of a square of side d, as shown the figure. Use Gauss' law to obtain the expression for the electric flux through the square.
The electric field intensity outside the charged conducting sphere of radius ‘R’, placed in a medium of permittivity ∈ at a distance ‘r’ from the centre of the sphere in terms of surface charge density σ is
Which statement is true for Gauss law -
Through two parallel wires A and B, 10A and 2A of currents are passed respectively in opposite directions. If the wire A is infinitely long and the length of the wire B is 2m, then force on the conductor B, which is situated at 10 cm distance from A, will be:
If the ratio of radii of two wires of same material is 3 : 1 and ratio of their lengths is 5 : 1, then the ratio of the normal forces that will produce the same extension in the length of two wires is:
Consider a sphere of radius R with charge density distributed as
ρ(r) = kr for r ≤ R
= 0 for r > R
- Find the electric field at all points r.
- Suppose the total charge on the sphere is 2e where e is the electron charge. Where can two protons be embedded such that the force on each of them is zero. Assume that the introduction of the proton does not alter the negative charge distribution.
- Obtain the expression for the electric field intensity due to a uniformly charged spherical shell of radius R at a point distant r from the centre of the shell outside it.
- Draw a graph showing the variation of electric field intensity E with r, for r > R and r < R.