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Question
An ion with mass number 56 contains 3 units of positive charge and 30.4% more neutrons than electrons. Assign the symbol to this ion.
Solution
Let the number of electrons present in ion `"A"^(3+)` be x
∴ Number of neutrons in it = x + 30.4% of x = 1.304 x
Since the ion is tripositive,
⇒ Number of electrons in neutral atom = x + 3
∴ Number of protons in neutral atom = x + 3
Given,
Mass number of the ion = 56
`therefore (x + 3) + (1.304 x) = 56`
2.304 x = 53
`x = 53/2.304`
x = 23
∴ Number of protons = x + 3 = 23 + 3 = 26
∴ The symbol of the ion `""_26^56"Fe"^(3+)`
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