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Question
An object moves 18 m in the first 3 s, 22 m in the next 3 s and 14 m in the last 3 s. What is its average speed?
Solution
Given, s1 = 18 m, t1 = 3 s, s2 = 22 m, t2 = 3 s, s3 = 14 m, t3 = 3 s
Average speed = ?
Average speed = `"Total distance"/"Total Time"`
Average speed = `(s_1 + s_2 + s_3)/(t_1 + t_2 + t_3)`
= `(18 + 22 + 14)/(3 + 3 + 3)`
= `54/9`
= 6 m/s.
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