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An object moves 18 m in the first 3 s, 22 m in the next 3 s and 14 m in the last 3 s. What is its average speed? - Science and Technology

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Question

An object moves 18 m in the first 3 s, 22 m in the next 3 s and 14 m in the last 3 s. What is its average speed?

Numerical

Solution

Given, s1 = 18 m, t1 = 3 s, s2 = 22 m, t2 = 3 s, s3 = 14 m, t3 = 3 s

Average speed = ?

Average speed = `"Total distance"/"Total Time"`

Average speed = `(s_1 + s_2 + s_3)/(t_1 + t_2 + t_3)`

= `(18 + 22 + 14)/(3 + 3 + 3)`

= `54/9`

= 6 m/s.

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Chapter 1: Laws of Motion - Exercises [Page 17]

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Balbharati Science and Technology [English] 9 Standard Maharashtra State Board
Chapter 1 Laws of Motion
Exercises | Q 7. a) | Page 17
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