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Question
An object was launched from a place P in constant speed to hit a target. At the 15th second, it was 1400 m from the target, and at the 18th second 800 m away. Find time taken to hit the target
Solution
Let us take the time T along the x-axis and the Distance D along the y-axis.
Given when time T = 15s, the distance D = 1400 m
The corresponding point is (15, 1400)
Also when time T = 18s, the distance D = 800 m.
The corresponding point is (18, 800)
Time taken to hit the Target:
When the target is reached D = 0
∴ (1) ⇒ T = `(1400 - 0)/200 + 15`
T = `1400/200 + 15`
T = 7 + 15
= 22 seconds
∴ The time taken to hit the target is 22 seconds
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