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Answer the following Cerium and Terbium behave as good oxidising agents in the +4 oxidation state. Explain. - Chemistry

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Question

Answer the following

Cerium and Terbium behave as good oxidising agents in the +4 oxidation state. Explain.

Answer in Brief

Solution

i. Cerium (Ce) and Terbium (Tb) show +4 oxidation states. Their electronic configurations are given below:

Ce = [Xe] 4f1 5d1 6s2 ; Ce4+ = [Xe]

Tb = [Xe] 4f9 6s2       ; Tb4+ = [Xe] 4f7

ii. It is clear from the configuration of Ce that Ce4+ is favoured by its noble gas configuration. But it can be easily converted into stable Ce3+ by a gain of an electron. Due to this reason, Ce4+ is a good oxidizing agent.

iii. Similarly, Tb4+ ion is stabilized due to a half-filled f-subshell. It can be easily converted into stable Tb3+ by gain of an electron. Due to this reason, Tb4+ is a good oxidizing agent.

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Inner Transition (f-block) Elements: Lanthanoids and Actinoids
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Chapter 8: Transition and Inner transition Elements - Exercises [Page 191]

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Balbharati Chemistry [English] 12 Standard HSC
Chapter 8 Transition and Inner transition Elements
Exercises | Q 3.1 | Page 191
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