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Question
Calculate the amplification factor of a triode valve that has plate resistance of 2 kΩ and transconductance of 2 millimho.
Solution
Given:-
Plate resistance,
`r_p=2kOmega`
Transconductance of plate,
`g_m=2"mili mho"=2xx10^-3"mho"`
Therefore, the amplification factor is given as:-
`mu=r_pxxg_m`
`mu=2xx10^3xx2xx10^-3=4`
That is, amplification factor is 4.
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