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Question
Calculate the following:
The temp, at which 500 cc. of a gas ‘X’ at temp. 293K occupies half it’s original volume [pressure constant].
Solution
V1 = 500 cc
T1 = 293 K
V2 = `500/2 = 250` cc
T2 = ?
At constant pressure
`"V"_1/"T"_1 = "V"_2/"T"_2`
∴ T2 = `("T"_1"V"_2)/"V"_1`
`= (293 xx 250)/500 = 146.5` K
= 146.5 − 273 = −126.5°C
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