Advertisements
Advertisements
Question
Calculate the following:
The volume at s.t.p. occupied by a gas ‘Z’ originally occupying 1.57 dm3 at 310.5K and 75 cm. press. of Hg.
Solution
Initial conditions
V1 = 1.57 dm3
P1 = 75 cm
T1 = 310.5 K
Final conditions
V2 = ?
P2 = 76 cm
T2 = 273 K
Using gas equation `("P"_1"V"_1)/"T"_1 = ("P"_2"V"_2)/"T"_2`
`therefore "V"_2 = ("P"_1"V"_1"T"_1)/("T"_1"P"_2)`
`= (75 xx 1.57 xx 273)/(310.5 xx 76) = 1.36 "dm"^3`
APPEARS IN
RELATED QUESTIONS
How is molecular motion related with temperature?
The molecular theory states that the pressure exerted by a gas in a closed vessel results from the gas molecules striking against the walls of the vessel. How will the pressure change if
- The temperature is doubled keeping the volume constant
- The volume is made half of its original value keeping the T constant
State the following:
STP conditions
Fill in the blanks:
The average kinetic energy of the molecules of a gas is proportional to the ………….
What volume will a gas occupy at 740 mm pressure which at 1480 nun occupies 500 cc? [Temperature being constant]
A fixed mass of a gas has a volume of 750 cc at—23°C and 800 mm pressure. Calculate the pressure for which its volume will be 720 cc. The temperature being - 3°C.
Calculate the following:
The temp, at which 500 cc. of a gas ‘X’ at temp. 293K occupies half it’s original volume [pressure constant].
Calculate the following:
The volume at s.t.p. occupied by a gas “Y” originally occupying 760 cc. at 300K and 70 cm. press, of Hg.
Calculate the following:
The volume at s.t.p. occupied by a gas ‘Q’ originally occupying 153.7 cm3 at 287K and 750 mm. pressure [vapour pressure of gas ‘Q’ at 287K is 12 mm of Hg.]
Calculate the following:
The temperature to which a gas ‘P’ has to be heated to triple it’s volume, if the gas originally occupied 150 cm3 at 330K [pressure remaining constant].