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Question
Calculate the length of the second’s pendulum on the surface of the moon when acceleration due to gravity on the moon is 1.63 ms−2.
Solution
Length of second’s pendulum = l =?
Acceleration due to gravity on the surface of the moon
= gm = 1.63 ms−2
Time period = T = 2 s
T = `2πsqrt("l"/"g")`
2 = `2xx22/7xxsqrt("l"/1.63)`
`sqrt("l"/1.63)=7/22`
Squaring both sides
`"l"/1.63=49/484`
l = `49/484xx1.63`
l = 0.165 m
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