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Question
Calculate the time period of a simple pendulum of length 0. 84 m when g = 9.8 ms−2.
Numerical
Solution
Length of the pendulum = l = 0.84 m
g = 9.8 ms−2
Time period (T) = `2πsqrt("l"/"g")=2xx22/7xxsqrt(0.84/9.8)`
= `44/7xx0.2928`
= 1.84 s
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