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Maharashtra State BoardSSC (English Medium) 7th Standard

Construct a triangle of the measures given below. In ∆PQR, l(PQ) = 4.5 cm, l(PR) = 11.7 cm, m ∠PQR = 90°. - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Construct a triangle of the measures given below.

In ∆PQR, l(PQ) = 4.5 cm, l(PR) = 11.7 cm, m ∠PQR = 90°.
Geometric Constructions

Solution

Steps of construction:

  1. Draw the Base:
    • Draw PQ = 4.5 cm using a ruler.
  2. Construct the Right Angle at Q:
    • Place the protractor at point Q on PQ.
    • Mark a 90 angle and draw a perpendicular line from Q.
  3. Locate Point R:
    • Set your compass to measure PR = 11.7 cm.
    • Place the compass point at P and draw an arc that intersects the perpendicular line from Q.
    • Label the intersection as point R.
  4. Complete the Triangle:
    • Connect R to P and R to Q.

You now have ∆PQR with PQ = 4.5 cm, PR = 11.7 cm, and ∠PQR = 90.

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Chapter 1: Geometrical Constructions - Practice Set 5 [Page 6]

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Balbharati Mathematics [English] 7 Standard Maharashtra State Board
Chapter 1 Geometrical Constructions
Practice Set 5 | Q 4 | Page 6
Balbharati Integrated 7 Standard Part 1 [English Medium] Maharashtra State Board
Chapter 3.1 Geometrical Constructions
Practice Set 5 | Q 4. | Page 43

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