मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता ७ वी

Construct a triangle of the measures given below. In ∆PQR, l(PQ) = 4.5 cm, l(PR) = 11.7 cm, m ∠PQR = 90°. - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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प्रश्न

Construct a triangle of the measures given below.

In ∆PQR, l(PQ) = 4.5 cm, l(PR) = 11.7 cm, m ∠PQR = 90°.
भौमितिक रेखाचित्रे

उत्तर

Steps of construction:

  1. Draw the Base:
    • Draw PQ = 4.5 cm using a ruler.
  2. Construct the Right Angle at Q:
    • Place the protractor at point Q on PQ.
    • Mark a 90 angle and draw a perpendicular line from Q.
  3. Locate Point R:
    • Set your compass to measure PR = 11.7 cm.
    • Place the compass point at P and draw an arc that intersects the perpendicular line from Q.
    • Label the intersection as point R.
  4. Complete the Triangle:
    • Connect R to P and R to Q.

You now have ∆PQR with PQ = 4.5 cm, PR = 11.7 cm, and ∠PQR = 90.

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पाठ 1: Geometrical Constructions - Practice Set 5 [पृष्ठ ६]

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बालभारती Mathematics [English] 7 Standard Maharashtra State Board
पाठ 1 Geometrical Constructions
Practice Set 5 | Q 4 | पृष्ठ ६
बालभारती Integrated 7 Standard Part 1 [English Medium] Maharashtra State Board
पाठ 3.1 Geometrical Constructions
Practice Set 5 | Q 4. | पृष्ठ ४३

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