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Question
Construct a triangle ABC with BC = 7 cm, ∠B = 60° and AB = 6 cm. Construct another triangle whose sides are `3/4` times the corresponding sides of ∆ABC.
Solution
Given: A ∆ABC with BC=7 cm, ∠B=60° and AB=6 cm
Steps of Construction
1. Draw a line segment AB = 6 cm.
2. With B as centre, draw ∠B=60°.
3. With B as centre and radius BC = 7 cm, draw an arc.
4. Join AC to obtain ∆ABC.
5. Below AB, make an acute angle ∠BAX.
6. Along AX, mark off four points A1, A2, A3 and A4 such that AA1=A1A2=A2A3=A3A4
7. Join A4B
8. From A3, draw A3B'∥A4B.
9. From B', draw B'C'∥BC.
Thus, ∆AB'C' is the required triangle with each of its side `3/4` times the size of the corresponding sides of ∆ABC.
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