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Derive an Expression for Voltage Gain of the Amplifier and Hence Show that the Output Voltage is in Opposite Phase with the Input Voltage. - Physics

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Question

Derive an expression for voltage gain of the amplifier and hence show that the output voltage is in opposite phase with the input voltage.

Solution

For a transistor to act as an amplifier, operating point is fixed in the middle of its active region. An ac input signal vi is superimposed on bias VBB (dc). The output is taken between collector and ground. Applying Kirchhoff’ law to the output loop.

VCC=VCE+ICRC

VBB=VBE+IBRB

Vi≠0

Then, VBB+Vi=VBE+IBRB+ΔIB(RB+ri)

`because r_i=((DeltaV_(BE))/(DeltaI_B))_(V_(CE))`

`therefore v_i=DeltaI_B(R_B+r_i)`

`=rDeltaI_B`

`beta_(ac)=(DeltaI_C)/(DeltaI_B)=i_c/i_b`

It is current gain denoted by Ai.

Change IC due to change in IB causes a change in VCE and the voltage drop across resistor RC, because VCC is fixed.

∴ ΔVCC = ΔVCE + RCΔIC = 0

⇒ ΔVCE = − RCΔIC

Change in VCE is the output voltage Vo.

∴ Vo = ΔVCE = − βac RCΔIB

Voltage gain of amplifier

`A_V=V_o/V_i=(DeltaV_(CE))/(rDeltaI_B)`

`=-beta_(ac)R_c/r`

Negative sign represents that the output voltage is in opposite phase to input voltage.

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2016-2017 (March) All India Set 3

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