Advertisements
Advertisements
Question
Draw ∠ABC of measure 105° and bisect it.
Solution
Steps for construction:-
- Draw BC = 5 cm (any)
- Place the centre of the protractor on B along the base line BC
- Using protractor construct m∠ABC = 105°.
- Draw an arc with centre at B and any fixed radius.
- Mark the points of intersection of the arc with the arms as P and Q.
- Keeping the same radius and with centres P and Q, draw arcs.
- Mark the point of intersection of the arcs as D
- Join BD. BD is the angle bisector of ∠ABC.
APPEARS IN
RELATED QUESTIONS
Draw `angle ABC` of measure 80° and bisect it
Draw ∠ABC of measures 135°and bisect it.
Ponit M is the mid point of seg AB and AB = 14 then AM = ?
If Δ ABC ∼ Δ XYZ then complete the following brackets.
`(AB)/(XY) = /(YZ) = (AC)/`
Draw ∠ ARP= 115° and bisect it.
Write down the equation of X- axis.
Draw seg AB of length 5.7 cm and bisect it.
Prove that “That ratio of areas of two similar triangles is equal to the square of the ratio of their corresponding sides.”
Construct ∠ABC = 60° and bisect it
Construct ∠PQR = 115° and divide it into two equal parts
Draw Seg AB of length 9.7 cm. Take point P on it such that AP = 3.5 cm and A–P–B. Construct perpendicular to seg AB from point P.
Draw seg AB of length 4.5 cm and draw its perpendicular bisector
Point P is at a distance of 6 cm from line AB. Draw a circle of radius 4 cm passing through point P so that line AB is the tangent to the circle