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Earth also moves in circular orbit around sun once every year with on orbital radius of 1.5 × 1011 m. - Physics

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Question

Earth also moves in circular orbit around sun once every year with on orbital radius of 1.5 × 1011 m. What is the acceleration of earth (or any object on the surface of the earth) towards the centre of the sun? How does this acceleration compare with g = 9.8 m/s2?

Short Note

Solution

The orbital radius of the earth around the sun (R) = 1.5 × 1011 m

Time period = 1 yr = 365 day

= 365 × 24 × 60 × 60 s 

= 3.15 ×107 s

 Centripetal acceleration `(a_c) = Rω^2 = (5pi^2R)/T^2`

= `(4 xx (22/7)^2 xx 1.5 xx 10^11)/(3.15 xx 10^7)^2`

= `5.97 xx 10^-3` m/s2

∴ `a_c/g = (5.97 xx 10^-3)/9.8 = 1/1642`

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Chapter 4: Motion In a Plane - Exercises [Page 23]

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NCERT Exemplar Physics [English] Class 11
Chapter 4 Motion In a Plane
Exercises | Q 4.25 (b) | Page 23

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