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Question
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
Class Interval | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
Frequency | 4 | 12 | 21 | 18 | 15 | 7 | 3 |
Solution
We first construct the cumulative frequency table of the given distribution.
Class Interval | Frequency (f) | Cumulative Frequency |
0-10 | 4 | 4 |
10-20 | 12 | 16 |
20-30 | 21 | 37 |
30-40 | 18 | 55 |
40-50 | 15 | 70 |
50-60 | 7 | 77 |
60-70 | 3 | 80 |
Take a graph paper and draw both the axes .
On the x-axis , take a scale of 1 cm = 10 to represent the class intervals.
On the y-axis , take a scale of 1 cm = 10 to represents the frequency .
Now , plot the points (10,4),(20,16),(30,37),(40,55),(50,70),(60,77),(70,80)
Join them by a smooth curve to get the ogive.
No. of terms = n = 80
∴ Median = `(40+41)/2` = 40.5th term
Through mark of 40.5 on y-axis draw a line parallel to x-axis which meets the curve at A. From A, draw a perpendicular to x-axis which meets it at B.
The value of B is the median which is 32.
Lower Quartile (Q1) = `n/4 = 80/4` = 20th term
Through mark of 20 on y-axis draw a line parallel to x-axis which meets the curve at P. From P , draw a perpendicular to x-axis which meets it at Q.
The value of Q is the lower quartile which is 23.
Upper Quartile (Q3) = `(n xx 3)/4 = (80 xx 3)/4` = 60th term
Through mark of 60 on y-axis draw a line parallel to x-axis which meets the curve at R. From R, draw a perpendicular to -axis which meets it at S.
The value of S is the upper quartile which is 43.5.
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