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Evaluate n!(n-r)!, when n = 9, r = 5 - Mathematics

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Question

Evaluate `(n!)/((n-r)!)`, when n = 9, r = 5

Sum

Solution

When n = 9, r = 5  `(n!)/((n-r)!)  = (9!)/((9 - 5)!) = (9!)/(4!) = (9  xx 8  xx 7  xx 6  xx  5  xx  4!)/(4!)`

= 9 x 8 x 7 x 6 x 5 = 15120 

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Chapter 7: Permutations and Combinations - Exercise 7.2 [Page 141]

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NCERT Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Exercise 7.2 | Q 5.2 | Page 141

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