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Question
Evaluate : `∫sin^2x` dx
Sum
Solution
Let I = `∫sin^2x` dx
∴ I = `∫(1 - cos2x)/2`dx
∴ I = `1/2[∫1dx - ∫cos2x dx]`
∴ I = `1/2[x - (sin2x)/2] + C`
∴ I = `x/2 - (sin2x)/4 + C`
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Indefinite Integration - Definition of an Integral
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