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Evaluate the following : limx→∞[8x2+5x+32x2-7x-5]4x+38x-1 - Mathematics and Statistics

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Question

Evaluate the following :

`lim_(x -> ∞) [(8x^2 + 5x + 3)/(2x^2 - 7x - 5)]^((4x + 3)/(8x - 1))`

Sum

Solution

`lim_(x -> ∞) [(8x^2 + 5x + 3)/(2x^2 - 7x - 5)]^((4x + 3)/(8x - 1))`

= `[lim_(x -> ∞) ((8x^2 + 5x + 3)/(2x^2 - 7x - 5))]^(lim_(x -> ∞)(4x + 3)/(8x - 1))`

Consider

`lim_(x -> ∞) (8x^2 + 5x + 3)/(2x^2 - 7x - 5)`

= `lim_(x -> ∞) [((8x^2 + 5x + 3)/x^2)/((2x^2 - 7x - 5)/x^2)]   ...[("Divide Numerator and"),("Denominator by"  x^2)]`

= `(lim_(x -> ∞)(8 + 5/x + 3/x^2))/(lim_(x -> ∞)(2 - 7/x - 5/x^2))`

= `(8 + 0 + 0)/(2 - 0 - 0)  ...[lim_(x -> ∞) 1/x^"k" = 0, "k" > 0]`

= 4

Consider

`lim_(x -> ∞) (4x + 3)/(8x - 1)` 

= `lim_(x -> ∞) ((4x + 3)/x)/((8x - 1)/x)`  ...[Divide Numerator and Denominator by x]

= `(lim_(x -> ∞)(4 + 3/x))/(lim_(x -> ∞)(8 - 1/x)`

= `(4 + 0)/(8 - 0)   ...[lim_(x -> ∞) 1/x = 0]`

= `1/2`

Required limit = `(4)^(1/2)` = 2

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Limit at Infinity
  Is there an error in this question or solution?
Chapter 7: Limits - Miscellaneous Exercise 7.2 [Page 159]

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